16t^2-31t-6=4

Solution for 16t^2-31t-6=4 equation:

16t^2-31t-6=4

We move all terms to the left:

16t^2-31t-6-(4)=0

We add all the numbers together, and all the variables

16t^2-31t-10=0

a = 16; b = -31; c = -10;
Δ = b2-4ac
Δ = -312-4·16·(-10)
Δ = 1601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1601}}{2*16}=\frac{31-\sqrt{1601}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1601}}{2*16}=\frac{31+\sqrt{1601}}{32}
$